(5/t-3)-30/t^2-9

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Solution for (5/t-3)-30/t^2-9 equation: 


D( t )

t^2 = 0

t = 0

t^2 = 0

t^2 = 0

1*t^2 = 0 // : 1

t^2 = 0

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

5/t-(30/(t^2))-9-3 = 0

5/t-30*t^-2-9-3 = 0

5*t^-1-30*t^-2-12 = 0

t_1 = t^-1

5*t_1^1-30*t_1^2-12 = 0

5*t_1-30*t_1^2-12 = 0

DELTA = 5^2-(-30*(-12)*4)

DELTA = -1415

DELTA < 0

t belongs to the empty set

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